Question 1
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14,16x9=144,2x8=16
14+144+16=174
a)174 people can be seated in the whare kai.
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Question 2
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5x174=870
3x174=522
4x174=696
Roimata and her whanau would need to provide,
Pieces of vegetables- 870
Slices of meat- 522
Pieces of fruit- 696
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Question 3
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4people-1pk Biscuit, 4people x 40pk biscuits=160 people+1pk=172people+1pk-6bisuits=174 people/41.5 packs of biscuits.
Roimata will need 42 packs of biscuits and will be left with 6biscuits.
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Question 4 (a)
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174x300=52200
Roimata will need upto 52200ml of water.
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Question 4 (b)
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52200 divided by 1000=52.2L
52.2 divided by 2=26.1
They would need 27, 2L jugs of water.
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Question 5
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Roimata will have to set up 19 tables with the following amounts of fruits and biscuits.
1xtable/14people
4x14=56 fruits
3x14=42 biscuits
16xtables/9people
9x4=36 fruits
9x3=27 biscuits
2xtables/8people
8x4=32 fruits
8x3=24 biscuits
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